Find two positive integers that satisfy the requirement. The product of two consecutive odd integers is 483.

Answer:The two positive integers that satisfy the requirement are 21 and 23Step-by-step explanation:Letx ----> the first consecutive odd integerx+2 ---> the second consecutive odd integerwe know that[tex]x(x+2)=483[/tex]Apply distributive property left side[tex]x^2+2x=483[/tex][tex]x^2+2x-483=0[/tex]we know that The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to [tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex] in this problem we have [tex]x^2+2x-483=0[/tex]so [tex]a=1\\b=2\\c=-483[/tex] substitute in the formula [tex]x=\frac{-2(+/-)\sqrt{2^{2}-4(1)(-483)}} {2(1)}[/tex] [tex]x=\frac{-2(+/-)\sqrt{1,936}} {2)}[/tex] [tex]x=\frac{-2(+/-)44} {2)}[/tex] [tex]x=\frac{-2(+)44} {2)}=21[/tex] [tex]x=\frac{-2(-)44} {2)}=-23[/tex] sox=21x+2=23thereforeThe two positive integers that satisfy the requirement are 21 and 23